Problem 15.128 Challenge

พิจารณาการต่อแบบขนาน

จะได้\(\frac{1}{Z}=\frac{1}{1,200}+\frac{1}{j800}\)

\(Z =\frac{j2,400}{3.00 + j2.00}\)

\(Z =\frac{2,400∠90°}{3.61∠33.7°}\)

\(Z = 665∠56.3° Ω\)

จาก \(ΔV = IZ\)

\(\Delta V = (2.00∠0°)(665∠56.3°)\)

\(\Delta V = 1,330∠56.3° V\)

จาก \(I_{1} = \frac{\Delta V}{Z_{1}}=\frac{1,330∠56.3°}{1,200∠0°}= 1.11∠56.3° A\)

\(\therefore |I_{1}| = 1.11 A \;\blacksquare\)

จาก \(I_{2} = \frac{\Delta V}{Z_{2}}=\frac{1,330∠56.3°}{800∠90°}= 1.66∠33.7° A\)

\(\therefore |I_{2}| = 1.66 A \;\blacksquare\)

จาก \(AP = I_{rms}\Delta V_{rms}\)

\(AP =\frac{|I|}{2}\frac{|\Delta V|}{2}\)

\(AP =\frac{(2.00)}{2}\frac{(1,330)}{2}\)

\(AP = 1.33 kW \;\blacksquare\)