Problem 4.6 Challenge
หัวข้อ: ศูนย์กลางมวลและศูนย์ถ่วง (Center of Mass and Center of Gravity)
\(\therefore \vec{r}_{cm}=\frac{2w}{3}+\frac{h}{3}\;\blacksquare\)
ดูวิธีทำ
หาจุดศูนย์กลางมวลในแกน x
\(yx_{cm}=\frac{\int xdm}{M}\)
\(hx_{cm}=\frac{1}{M}\int xσdA\)
\(dm = σdA\)
\(x_{cm}=\frac{σ}{M}\int xydx\)
\(x_{cm}=\frac{M}{M\frac{1}{2}wh}\int x\frac{hx}{w}dx\)
\(_{w}\)
x
\(\frac{y =\frac{hx}{w}}{dxw}x_{cm}=\frac{2}{w^{2}}\int x^{2}dx\)
\(_{0}\)
x
\(x_{cm}=\frac{2w}{3}\)
หาจุดศูนย์กลางมวลในแกน y
\(yy_{cm}=\frac{\int ydm}{M}\)
\(dm = σdA\)
\(hy_{cm}=\frac{1}{M}\int yσdA\)
\(y_{cm}=\frac{σ}{M}\int y(w - x)dy\)
xw - x
\(y_{cm}=\frac{M}{M\frac{1}{2}wh}\int y(w -\frac{wy}{h})dy\)
\(x^{h}\)
\(\frac{y}{dxw}\)
\(y_{cm}=\frac{2}{h}\int (y-\frac{y^{2}}{h})dy\)
\(_{0}\)
\(y_{cm}=\frac{h}{3}\)
îĵ
\(\therefore \vec{r}_{cm}=\frac{2w}{3}+\frac{h}{3}\;\blacksquare\)