Problem 13.133

พิจารณาภาพวงจรหลังสับสวิตซ์

จาก \(C_{23} = C_{2} + C_{3}\)

\(C_{23} = (3.00 \mu F) + (1.0 \mu F)_{C_{1} = 1.00 \mu FC_{23}}\)

˜˜

\(C_{23} = 4.00 \mu F\)

˜

\(_{C_{4} = 12.00 \mu F}\)

จาก \(\frac{1}{C_{234}}=\frac{1}{C_{4}}+\frac{1}{C_{23}}\)

\(C_{234} =\frac{C_{23}C_{4}}{C_{23} + C_{4}}\)

\(C_{234} =\frac{(4.00 \mu F)(12.00 \mu F)}{(4.00 \mu F) + (12.00 \mu F)}= 3.00 \mu F\)

จาก \(ΣQ_{f}= \Sigma Q_{i}\)

\(Q_{1f}+ Q_{234}= Q_{1i}+ Q_{2i}+ Q_{3i}+ Q_{4i}\)

\(C_{1}\Delta V + C_{234}\Delta V = Q_{1} + 0 + 0 + 0\)

\(\Delta V =\frac{Q_{1}}{C_{1} + C_{234}}\)

\(\Delta V =\frac{40.0 \mu C}{(5.00 \mu F) + (3.00 \mu F)}\)

\(\Delta V = 5.00 V \;\blacksquare\)