Problem 13.23

กำหนดให้ \(q_{1} = -6.0\times 10^{-6} C, q_{2} = 10.0\times 10^{-6} C , r_{1} = 3.0 m\)

และ \(r_{2} = \sqrt{3.0^{2} + 4.0^{2}}= 5.0 m\)

จาก \(Σ\vec{E} = \vec{E}_{1} + \vec{E}_{2}\)

îîĵ

\(\Sigma \vec{E} =\frac{kq_{1}}{r_{1}^{2}}(- ) +\frac{kq_{2}}{r_{2}^{2}}(\frac{3.0}{5.0}-\frac{4.0}{5.0})\)

îîĵ

\(\Sigma \vec{E} = -6.0 + 2.2 - 2.9 kN/C\)

îĵ

\(\Sigma \vec{E} = -3.8 - 2.9 kN/C\)

\(|\Sigma \vec{E}| =\sqrt{(-3.8)^{2} + (-2.9)^{2}}kN/C\)

\(|\Sigma \vec{E}| = 4.8 kN/C \;\blacksquare\)